70k^2+115k+15=0

Solution for 70k^2+115k+15=0 equation:

70k^2+115k+15=0

a = 70; b = 115; c = +15;
Δ = b2-4ac
Δ = 1152-4·70·15
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9025}=95$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(115)-95}{2*70}=\frac{-210}{140}
=-1+1/2
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(115)+95}{2*70}=\frac{-20}{140}
=-1/7
$